A rectangular garden (60 m × 40 m) is surrounded by a road of width 2 m, the road is covered by tiles and the garden is fenced. If the total expenditure is Rs. 51600 and rate of fencing is Rs. 50 per metre, then the cost of covering 1 sq. m of road by tiles is :
A. Rs. 10
B. Rs. 50
C. Rs. 100
D. Rs. 150
Answer: Option C
Solution(By Examveda Team)
Length of the fence := 2(60 + 40) m
= 200 m
Cost of fencing :
= Rs. (200 × 50)
= Rs. 10000
Area of the road :
= [(64 × 44) - (60 × 40)] m2
= (2816 - 2400) m2
= 416 m2
Let the cost of tiling the road be Rs. x per sq.m
∴ 416x + 10000 = 51600
⇒ 416x = 41600
⇒ x = Rs. 100
Related Questions on Area
A. 15360 m2
B. 153600 m2
C. 30720 m2
D. 307200 m2
E. None of these
A. 2%
B. 2.02%
C. 4%
D. 4.04%
E. None of these
A. 16 cm
B. 18 cm
C. 24 cm
D. Data inadequate
E. None of these
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
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