A rectangular paper, when folded into two congruent parts had a perimeter of 34 cm for each part folded along one set of sides and the same is 38 cm when folded along the other set of sides. What is the area of the paper ?
A. 140 cm2
B. 240 cm2
C. 560 cm2
D. None of these
Answer: Option A
Solution(By Examveda Team)
When folded along breadth, we have :$$\eqalign{ & 2\left( {\frac{l}{2} \times b} \right) = 34 \cr & or,l + 2b = 34.....(i) \cr} $$
When folded along length, we have :
$$\eqalign{ & 2\left( {l \times \frac{b}{2}} \right) = 38 \cr & or,2l + b = 38.....(ii) \cr} $$
Solving (i) and (ii), we get :
$$l$$ = 14 and b = 10
∴ Area of the paper :
= (14 × 10) cm2
= 140 cm2
Related Questions on Area
A. 15360 m2
B. 153600 m2
C. 30720 m2
D. 307200 m2
E. None of these
A. 2%
B. 2.02%
C. 4%
D. 4.04%
E. None of these
A. 16 cm
B. 18 cm
C. 24 cm
D. Data inadequate
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The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
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