A rectangular tank measuring 5 m × 4.5 m × 2.1 m is dug in the centre of the field measuring 13.5 m by 2.5 m. The earth dug out is evenly spread over the remaining portion of the field. How much is the level of the field raised ?
A. 4 m
B. 4.1 m
C. 4.2 m
D. 4.3 m
Answer: Option C
Solution (By Examveda Team)
Volume of earth dug out :$$\eqalign{ & = \left( {5 \times 4.5 \times 2.1} \right){{\text{m}}^{\text{3}}} \cr & = 47.25\,{{\text{m}}^{\text{3}}} \cr} $$
Area over which earth is spread :
$$\eqalign{ & = \left( {13.5 \times 2.5 - 5 \times 4.5} \right){{\text{m}}^2} \cr & = \left( {33.75 - 22.5} \right){{\text{m}}^2} \cr & = 11.25\,{{\text{m}}^2} \cr} $$
$$\eqalign{ & \therefore {\text{Rise in level}} = \frac{{{\text{Volume}}}}{{{\text{Area}}}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \left( {\frac{{47.25}}{{11.25}}} \right)m \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 4.2\,m \cr} $$
This Question Belongs to Arithmetic Ability >> Volume And Surface Area
The width of the tank is bigger than the width of the field! How is this possible
Sir breadth of tank can be 4.5 metre if breadth of field is 2.5 m ??
length of field is 13.5 m so tank length 5 m is okay.