A right angled sector of radius $$r$$ cm is rolled up into a cone in such a way that the two binding radii are joined together. Then the curved surface area of the cone is

Solution (By Examveda Team)

$$\eqalign{ & \Rightarrow {\text{Circumference of sectors}} = \frac{{\pi r}}{2} \cr & \Rightarrow {\text{Circumference of base of cone of radius}} = 2\pi {r_1} \cr & \frac{{\pi r}}{2} = 2\pi {r_1} \Rightarrow {r_1} = \frac{r}{4} \cr & \therefore {\text{Radius of cone}} = \frac{r}{4} \cr & {\text{Curved surface area of cone}} = \pi {r_1}l \cr & l = {\text{slant height}} \cr & l = r \cr & \therefore {\text{Surface area of cone}} = \pi \times \frac{r}{4} \times r \Rightarrow \frac{{\pi {r^2}}}{4} \cr} $$