A robbery was done by a thief at a jewellery shop and he took 2 kg gold. The shop is 1125 m away from a policeman. The thief starts running at x km/h and the policeman starts chasing at 11 km/h at the same time. The policeman caught the thief in 810 sec. What is the distance run by the thief?

Solution (By Examveda Team)

$$\eqalign{ & \Rightarrow \frac{{1125}}{{\left( {11 - x} \right)\frac{5}{{18}}}} = 810 \cr & \Rightarrow \frac{{1125 \times 18}}{{\left( {11 - x} \right) \times 5}} = 810 \cr & \Rightarrow 5 = 11 - x \cr & \Rightarrow x = 6 \cr} $$
Distance of thief = 810 × 6 × $$\frac{5}{{18}}$$ = 1350 m Ans.