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A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be,

A. 10 m

B. 12 m

C. 14 m

D. 16 m

Answer: Option D


This Question Belongs to Civil Engineering >> Theory Of Structures

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Comments ( 2 )

  1. Aziz Panna
    Aziz Panna :
    4 years ago

    Given, slope = 0.002 rad
    And deflection= 10 mm
    If Simply Supported beam carries UDL ,
    then Slope = WL^3 / 24 EI
    And deflection = 5 WL^4 / 384 EI =10 mm (given)
    =》 (5 L / 16) * WL^3 /24 = 10 mm
    =》 (5L/16) * 0.002 = 10 mm
    =》 L = (10*16) / (5*0.002) = 16000 mm
    So, L = 16 m

  2. Ashna Aliyar
    Ashna Aliyar :
    4 years ago

    P

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