A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be,
A. 10 m
B. 12 m
C. 14 m
D. 16 m
Answer: Option D

Given, slope = 0.002 rad
And deflection= 10 mm
If Simply Supported beam carries UDL ,
then Slope = WL^3 / 24 EI
And deflection = 5 WL^4 / 384 EI =10 mm (given)
=》 (5 L / 16) * WL^3 /24 = 10 mm
=》 (5L/16) * 0.002 = 10 mm
=》 L = (10*16) / (5*0.002) = 16000 mm
So, L = 16 m
P