A runs $$\frac{7}{4}$$ times as fast as B. If A gives B a start of 300 m, how far must the winning post be if both A and B have to end the race at same time?
A. 1400 m
B. 700 m
C. 350 m
D. 210 m
Answer: Option B
Solution (By Examveda Team)
| . | A | B | Reason (ST=D) |
| Speed | 7 | 4 | Given |
| Time | 4 | 7 | Since, Speed ∝ $$\frac{1}{{{\text{Time}}}}$$ |
| Distance | 4 | 7 | Distance ∝ time |
This Question Belongs to Arithmetic Ability >> Speed Time And Distance
let,
total distance be x
B speed y
A speed 7y/4
ATQ
x/7y/4=x-300/y
=>y= 700