A runs $$\frac{7}{4}$$ times as fast as B. If A gives B a start of 300 m, how far must the winning post be if both A and B have to end the race at same time?

A. 1400 m

B. 700 m

C. 350 m

D. 210 m

Answer: Option B

Solution(By Examveda Team)

.	A	B	Reason (ST=D)
Speed	7	4	Given
Time	4	7	Since, Speed ∝ $$\frac{1}{{{\text{Time}}}}$$
Distance	4	7	Distance ∝ time

Now,
7x - 4x = 300 (A runs 7x m and B runs 4x)
x = 100
7x = 7 × 100 = 700 m
Winning post is 700 m away, As A runs 700 m to complete the race.