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A sector is formed by opening out a cone of base...

This question belongs to Arithmetic Ability Mensuration 3D
Mensuration 3D
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A sector is formed by opening out a cone of base radius 8 cm and heigh 6 cm. Then the radius of the sector is (in cm).

Answer & Solution
Correct Answer: Option C
Slant height of cone $$ = \sqrt {{8^2} + {6^2}} = 10{\text{ cm}}$$
Slant height of cone = Radius of sector = 10 cm
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