A ship whose hull length is 100 m is to travel at 10 m/sec. For dynamic similarity, at what velocity should a 1:25 model be towed through water ?
A. 10 m/sec
B. 25 m/sec
C. 2 m/sec
D. 50 m/sec
Answer: Option C
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Related Questions on Hydraulics and Fluid Mechanics
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B. 33 m/sec.
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D. 90 m/sec.
A. the weight of the body
B. more than the weight of the body
C. less than the weight of the body
D. weight of the fluid displaced by the body
The difference of pressure between the inside and outside of a liquid drop is
A. $${\text{p}} = {\text{T}} \times {\text{r}}$$
B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$
C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$
D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$
A. cannot be subjected to shear forces
B. always expands until it fills any container
C. has the same shear stress.at a point regardless of its motion
D. cannot remain at rest under action of any shear force
froude number
in this ques froude no of prototype =froude no of model
v/root gL=V'/ROOTg'L',
10/ROOT 100=V'/ROOT 100/25 (L'=100/25)
V' ROOT 4=2
Vp =10 m/s
Vm =?
Lr=1/25
So,
Vr=root Lr
Ans 2m/s
Please explain
=√(100)*(1/25)
=√4
=2
Use Vr=under root Lr
Please explain
How