A solid cylinder of mass M and radius R rolls down an inclined plane without slipping. The acceleration of center of mass of rolling cylinder is (where ‘$${\text{g}}$$’ is acceleration due to gravity and $$\theta $$ is inclination of plane with horizontal.)
A. $$\frac{1}{3}{\text{g}}\sin \theta $$
B. $$\frac{2}{3}{\text{g}}\cos \theta $$
C. $$\frac{2}{3}{\text{g}}\sin \theta $$
D. $${\text{g}}\sin \theta $$
Answer: Option C

Join The Discussion