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A solid cylinder of mass M and radius R rolls down an inclined plane without slipping. The acceleration of center of mass of rolling cylinder is (where ‘$${\text{g}}$$’ is acceleration due to gravity and $$\theta $$ is inclination of plane with horizontal.)

A. $$\frac{1}{3}{\text{g}}\sin \theta $$

B. $$\frac{2}{3}{\text{g}}\cos \theta $$

C. $$\frac{2}{3}{\text{g}}\sin \theta $$

D. $${\text{g}}\sin \theta $$

Answer: Option C


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Related Questions on Applied Mechanics and Graphic Statics

The resultant of two forces P and Q acting at an angle $$\theta $$, is

A. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{P}}\sin \theta $$

B. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta $$

C. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\tan \theta $$

D. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta } $$

E. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\sin \theta } $$