A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The moment of resistance of the beam for the same maximum permissible stress $$\sigma $$ in timber and steel will be (where Young's modulus of steel is m times that of the timber).
A. $$\sigma \left( {\frac{{{\text{B}}{{\text{D}}^2} + {\text{mb}}{{\text{d}}^2}}}{{6{\text{D}}}}} \right)$$
B. $$\sigma \left( {\frac{{{\text{B}}{{\text{D}}^3} + {\text{mb}}{{\text{d}}^3}}}{{6{\text{D}}}}} \right)$$
C. $$\sigma \left( {\frac{{{\text{B}}{{\text{D}}^2} + {\text{mb}}{{\text{d}}^3}}}{{4{\text{D}}}}} \right)$$
D. $$\sigma \left( {\frac{{{\text{B}}{{\text{D}}^2} + {\text{mb}}{{\text{d}}^2}}}{{4{\text{D}}}}} \right)$$
Answer: Option B
A. $$\frac{2}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
Principal planes are subjected to
A. Normal stresses only
B. Tangential stresses only
C. Normal stresses as well as tangential stresses
D. None of these
A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$
D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$
A. $$\frac{{\text{M}}}{{\text{T}}}$$
B. $$\frac{{\text{T}}}{{\text{M}}}$$
C. $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D. $$\frac{{2{\text{T}}}}{{\text{M}}}$$
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