A student goes to school at a speed of $$5\frac{1}{2}$$ km/h and returns at a speed of 4 km/h. If he takes $$4\frac{3}{4}$$ hours for the entire journey, then total distance covered by the student (in km) is:
A. 22
B. 16
C. 24
D. 11
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {\text{Total distance}} = \frac{{{S_1} \times {S_2}}}{{{S_1} + {S_2}}} \times {\text{Total time}} \cr & = \frac{{5\frac{1}{2} \times 4}}{{5\frac{1}{2} + 4}} \times 4\frac{3}{4} \cr & = \frac{{\frac{{11}}{2} \times 4}}{{\frac{{11}}{2} + 4}} \times \frac{{19}}{4} \cr & = \frac{{22}}{{\frac{{19}}{2}}} \times \frac{{19}}{4} \cr & = \frac{{44}}{{19}} \times \frac{{19}}{4} \cr & = 11{\text{ km}} \cr & {\text{One side distance}} = 11{\text{ km}} \cr & {\text{Both side distance}} = 2 \times 11 = 22{\text{ km}} \cr} $$Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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