A student goes to school at the rate of $$2\frac{1}{2}$$ km/hr and reaches 6 min late. If he travels at the speed of 3 km/hr, he is 10 min early. The distance (in km) between the school and the house is :
A. 5 km
B. 4 km
C. 3 km
D. 1 km
Answer: Option B
Solution (By Examveda Team)

= 6 - 5 = 1 unit → $$\frac{16}{60}$$
15 units → $$\frac{16}{60}$$ × 15 = 4
∴ Required distance = 4 km

how you find out 5hr and 6hr?