A student walks from his house at a speed of $$2\frac{1}{2}$$ km per hour and reaches his school 6 minutes late. The next day he increases his speed by 1 km per hours and reaches 6 minutes before school time. How far is the school from his house ?
A. $$\frac{5}{4}$$ km
B. $$\frac{7}{4}$$ km
C. $$\frac{9}{4}$$ km
D. $$\frac{11}{4}$$ km
Answer: Option B
Solution(By Examveda Team)
Difference between his reaching time :
= (14 - 10) hrs
= 4 hrs
= 4 hrs → 6m + 6m
(late + before)
= 4 hrs → 12 minutes
= 1 unit = $$\frac{12}{4 × 60}$$ km
($$\because $$ 1 m = 60 seconds)
1 unit = $$\frac{1}{20}$$ km
Then, 35 units :
= 35 × $$\frac{1}{20}$$ km
= $$\frac{7}{4}$$ km
Then the distance between his house and school is = $$\frac{7}{4}$$ km
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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