A thief, pursued by a policeman, was 100 m ahead at the start. If the ratio of the speed of the policeman to that of the thief was 5 : 4, then how far could the thief go before he was caught by the policeman ?
A. 80 m
B. 200 m
C. 400 m
D. 600 m
Answer: Option C
Solution(By Examveda Team)
Let the thief be caught x metres from the place where the policeman started running.Let the speed of the policeman and the thief be 5y m/s and 4y m/s respectively.
Then, time taken by the policeman to cover x metres = time taken by the thief to cover (x - 100) m
$$\eqalign{ & \Rightarrow \frac{x}{{5y}} = \frac{{\left( {x - 100} \right)}}{{4y}} \cr & \Rightarrow 4x = 5\left( {x - 100} \right) \cr & \Rightarrow x = 500 \cr} $$
So, the thief ran (500 - 100) i.e., 400 m before being caught.
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
Join The Discussion