A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 metres ahead of the policeman, then the time required for the policeman to catch the thief will be :

A. 2 minutes

B. 3 minutes

C. 6 minutes

D. 10 minutes

Answer: Option B

Solution(By Examveda Team)

Relative speed = (10 - 8) km/hr = 2 km/hr
Required time = Time taken to cover 100 m at relative speed :
$$\eqalign{ & = \left( {\frac{{100}}{{2000}}} \right){\text{hr}} \cr & = \left( {\frac{1}{{20}}} \right){\text{hr}} \cr & = \left( {\frac{1}{{20}} \times 60} \right){\text{min}} \cr & = 3\text{ minutes} \cr} $$