A thief sees a jeep at a distance of 250 m, coming towards him at 36 km/h. Thief takes 5 seconds to realize that there is nothing but the police is approaching him by the jeep and start running away from police at 54 km/h. But police realise after 10 second, when the thief starts running away, that he is actually a thief and gives chase at 72 km/h. How long after thief saw police did catchup with him and what is the distance police had travel to do so?
A. 50 s, 1000 m
B. 65 s, 1150 m
C. 65 s, 1300 m
D. 45 s, 1050 m
E. None of these
Answer: Option B
Solution (By Examveda Team)
Initial speed of the police = 10 m/s Increased speed of the Police = 20 m/s Speed of the thief = 15 m/s Initial difference between speed of thief and police = 250 m After 5 seconds difference between thief and police = 200 + (5 × 10) = 250 m Now, the time required by police to catch the thief = $$\frac{{250}}{5}$$ = 50 s Total time = 50 + 15 = 65 s Total distance = 1000 + (15 × 10) = 1150 m.This Question Belongs to Arithmetic Ability >> Speed Time And Distance
how do we know whether the distance travelled by the police is that which they travel AFTER realizing he's a thief? why did the solutions consider the distance travelled by police BEFORE deciding to chase the thief?