A tiger is 50 of its own leaps behinds a deer. The tiger takes 5 leaps and per minutes to the deer's 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it caches the deer?
A. 600 m
B. 700 m
C. 800 m
D. 1000 m
E. None of these
Answer: Option C
Solution (By Examveda Team)
Speed of tiger = 40 m/min Speed of deer = 20 m/min. Relative speed = 40 - 20 = 20 m/min. Initial difference in distance = 50 × 8 = 400 m Time take to catch = $$\frac{{400}}{{20}}$$ = 20 min. Distance traveled in 20 min,= 20 × 40 = 800 mThis Question Belongs to Arithmetic Ability >> Speed Time And Distance
ye 40 aur 20m /min aaya kha se