A tiger is 50 of its own leaps behinds a deer. The tiger takes 5 leaps and per minutes to the deer's 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it caches the deer?

A. 600 m

B. 700 m

C. 800 m

D. 1000 m

E. None of these

Answer: Option C

Solution(By Examveda Team)

Speed of tiger = 40 m/min
Speed of deer = 20 m/min.
Relative speed = 40 - 20 = 20 m/min.
Initial difference in distance = 50 × 8 = 400 m
Time take to catch = $$\frac{{400}}{{20}}$$ = 20 min.
Distance traveled in 20 min,
= 20 × 40
= 800 m