A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is :

A. 100 kmph

B. 110 kmph

C. 120 kmph

D. 130 kmph

Answer: Option C

Solution(By Examveda Team)

Let speed of the car be x kmph
Then, speed of the train :
$$ = \frac{{150}}{{100}}x = \left( {\frac{3}{2}x} \right){\text{ kmph}}$$
$$\eqalign{ & \therefore \frac{{75}}{x} - \frac{{75}}{{\frac{3}{2}x}} = \frac{{125}}{{10 \times 60}} \cr & \Leftrightarrow \frac{{75}}{x} - \frac{{50}}{x} = \frac{5}{{24}} \cr & \Leftrightarrow x = \left( {\frac{{25 \times 24}}{5}} \right) \cr & \Leftrightarrow x = 120{\text{ kmph}} \cr} $$