A train covers a distance of $$193\frac{1}{3}$$ km in $$4\frac{1}{4}$$ hours with one stoppage of 10 minutes, two of 5 minutes and one of 3 minutes on the way. The average speed of the train is :
A. 48 km/hr
B. 50 km/hr
C. 55 km/hr
D. 60 km/hr
Answer: Option B
Solution(By Examveda Team)
Actual time taken for the journey := 4 hrs 15 min - (10 + 2 × 5 + 3) min
= 4 hrs 15 min - 23 min
= 3 hrs 52 min
= $$3\frac{26}{30}$$ hrs
= $$\frac{116}{30}$$ hrs
∴ Average speed :
$$\eqalign{ & = \left( {\frac{{580}}{3} \times \frac{{30}}{{116}}} \right){\text{ km/hr}} \cr & = 50{\text{ km/hr}} \cr} $$
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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