A train met with an accident 120 km from station A. It completed the remaining journey at $$\frac{5}{6}$$ of its previous speed and reached 2 hour late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?
A. 100 km/h
B. 12 km/h
C. 60 km/h
D. 50 km/h
Answer: Option C
Solution (By Examveda Team)
A ____100 km____ P1 ________300 km_____ P2 ____X______ B If speed becomes $$\frac{5}{6}$$ then time taken will be $$\frac{6}{5}$$ of original time. Thus, extra time = 2 hour $$\frac{1}{5}$$ = 2 hour Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. It means It covers 300 km distance in 5 hours. then speed = $$\frac{{300}}{5}$$ = 60 km/hThis Question Belongs to Arithmetic Ability >> Speed Time And Distance
300/5x - 300/6x = 1
60/x - 50/x = 1
x = 10
6x = 60 km/hr
speed=6:5
time=5:6[gap 1]
so speed=300/5=60km/hr...(ans)
Time difference between first case and 2nd case is 1 hr
This 1hour late is becoz of that 300 km distance
So
In first case that 300 km is travelled by 5x/6 speed
And in second case that 300 km is travelled by x speed
So now
300/5x/6 - 300/x = 1/
So X = 60 kmph.
Actual time=10h
So distance = 60*10=600km
What is the answer if we asked distance between 2 stations