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A train met with an accident 120 km from station A. It completed the remaining journey at $$\frac{5}{6}$$ of its previous speed and reached 2 hour late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?
Answer & Solution
Correct Answer:
Option
C
A ____100 km____ P1 ________300 km_____ P2 ____X______ B
If speed becomes $$\frac{5}{6}$$ then time taken will be $$\frac{6}{5}$$ of original time.
Thus, extra time = 2 hour
$$\frac{1}{5}$$ = 2 hour
Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours.
It means It covers 300 km distance in 5 hours.
then speed = $$\frac{{300}}{5}$$ = 60 km/h
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Login60/x - 50/x = 1
x = 10
6x = 60 km/hr
time=5:6[gap 1]
so speed=300/5=60km/hr...(ans)
This 1hour late is becoz of that 300 km distance
So
In first case that 300 km is travelled by 5x/6 speed
And in second case that 300 km is travelled by x speed
So now
300/5x/6 - 300/x = 1/
So X = 60 kmph.
Actual time=10h
So distance = 60*10=600km