A train met with an accident 120 km from station A. It completed the remaining journey at $$\frac{5}{6}$$ of its previous speed and reached 2 hour late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?
A. 100 km/h
B. 12 km/h
C. 60 km/h
D. 50 km/h
Answer: Option C
Solution(By Examveda Team)
A ____100 km____ P1 ________300 km_____ P2 ____X______ B If speed becomes $$\frac{5}{6}$$ then time taken will be $$\frac{6}{5}$$ of original time. Thus, extra time = 2 hour $$\frac{1}{5}$$ = 2 hour Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. It means It covers 300 km distance in 5 hours. then speed = $$\frac{{300}}{5}$$ = 60 km/hThis Question Belongs to Arithmetic Ability >> Speed Time And Distance
Join The Discussion
Comments ( 4 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
300/5x - 300/6x = 1
60/x - 50/x = 1
x = 10
6x = 60 km/hr
speed=6:5
time=5:6[gap 1]
so speed=300/5=60km/hr...(ans)
Time difference between first case and 2nd case is 1 hr
This 1hour late is becoz of that 300 km distance
So
In first case that 300 km is travelled by 5x/6 speed
And in second case that 300 km is travelled by x speed
So now
300/5x/6 - 300/x = 1/
So X = 60 kmph.
Actual time=10h
So distance = 60*10=600km
What is the answer if we asked distance between 2 stations