A train of length 287 m, running at 80 km/h, crosses another train moving in the opposite direction at 37 km/h in 18 second. What is the length of the other train?

Solution (By Examveda Team)

$$\eqalign{ & \frac{{\left( {287 + x} \right)}}{{\left( {80 + 37} \right) \times \frac{5}{{18}}}} = 18 \cr & \left( {287 + x} \right) = 18\left( {80 + 37} \right) \times \frac{5}{{18}} \cr & 287 + x = 117 \times 5 \cr & 287 + x = 585 \cr & x = 585 - 287 \cr & x = 298{\text{ m}} \cr} $$