A train passes two persons walking in the same direction at a speed of 3 kmph and 5 kmph respectively in 10 seconds and 11 seconds respectively. The speed of the train is
A. 28 kmph
B. 27 kmph
C. 25 kmph
D. 24 kmph
Answer: Option C
A. 28 kmph
B. 27 kmph
C. 25 kmph
D. 24 kmph
Answer: Option C
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
3*10=30
5*11=55
Actual speed=55-30=25
time =1
Speed=25
Train 1=3*10=30
Train2=5*11=55
Actual speed->55-30=25
The speed of train=25kmph
3_ _ _ _ _ 5
10_ _ _ _ _11
3*10=30_ _ _5*11=55
time diff=11-10=1
speed=55-30=25
How do you get 5/18 in both the equations
18x=55s-275. 18x=50s-150. Then equate two equations... We will get the speed of train