A train running at $$\frac{7}{11}$$ of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed ?
A. 7 hr
B. 8 hr
C. 14 hr
D. 16 hr
Answer: Option B
Solution(By Examveda Team)
New speed = $$\frac{7}{11}$$ of usual speed∴ New time = $$\frac{11}{7}$$ of usual time
So, $$\frac{11}{7}$$ of usual time = 22 hrs
⇒ Usual time :
= $$\frac{22 × 7}{11}$$
= 14 hrs
Hence, time saved = (22 - 14) = 8 hrs
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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