A train started from station A and proceeded towards station B at a speed of 48 km/hr. Forty-five minutes later another train started from station B and proceeded towards station a at 50 km/hr. If the distance between the two stations is 232 km, at what distance from station A will the trains meet ?

Solution(By Examveda Team)

Suppose the trains meet after x hrs
Then,
Distance covered by 1^st train in x hrs + Distance covered by 2^nd train in $$\left( {x - \frac{3}{4}} \right)$$  hrs = 232 km
$$\eqalign{ & \Rightarrow 48x + 50\left( {x - \frac{3}{4}} \right) = 232 \cr & \Rightarrow 98x = 232 + \frac{{75}}{2} \cr & \Rightarrow 98x = \frac{{539}}{2} \cr & \Rightarrow x = \frac{{539}}{{196}}{\text{ hrs}} \cr} $$
Required distance = Distance travelled by 1^st train in $$\left( {\frac{{539}}{{196}}} \right)$$  hrs
$$\eqalign{ & = \left( {48 \times \frac{{539}}{{196}}} \right){\text{km}} \cr & = 132{\text{ km}} \cr} $$