A train travelling with a speed of 60 kmph catches another train travelling in the same direction and then leaves it 120 m behind in 18 seconds. The speed of the second train is
A. 26 kmph
B. 35 kmph
C. 36 kmph
D. 63 kmph
Answer: Option C
Solution(By Examveda Team)
Let speed of the 2nd train is S m/sec. And, 60 kmph $$ = \frac{{60 \times 5}}{{18}} = \frac{{50}}{3}$$ m/sec. As trains are traveling in same distance, Then Relative distance, $$\eqalign{ & = \frac{{60 \times 5}}{{18}} = \frac{{50}}{3} \cr & \frac{{50}}{3} - S = \frac{{120}}{{18}} \cr & \Rightarrow \frac{{50 - 3S}}{3} = \frac{{20}}{3} \cr & \Rightarrow 50 - 3S = 20 \cr & \Rightarrow 3S = 50 - 20 \cr & \Rightarrow 3S = 30 \cr & \therefore S = 10\,\,{\text{m/sec}} \cr} $$ Or, Speed of the 2nd train = $${\text{10}} \times \frac{{18}}{5}$$ = 36 kmph.Join The Discussion
Comments ( 2 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
to make m/sec to km/h ,multiplying 18/5
Can you tell me about that 18/5 at the last