A triangle of area 9y cm² has been drawn such that its area is equal to the area of an equilateral triangle of side 6 cm. The value of y would be :

A. $$\sqrt 2 $$

B. $$\sqrt 3 $$

C. $$ 2 $$

D. $$ 3 $$

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & 9y = \frac{{\sqrt 3 }}{4} \times 6 \times 6 \cr & \Rightarrow y = \left( {\frac{{\sqrt 3 }}{4} \times 6 \times 6 \times \frac{1}{9}} \right) \cr & \Rightarrow y = \sqrt 3 \cr} $$