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A triangle of area 9y cm2 has been drawn such that its area is equal to the area of an equilateral triangle of side 6 cm. The value of y would be :
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& 9y = \frac{{\sqrt 3 }}{4} \times 6 \times 6 \cr
& \Rightarrow y = \left( {\frac{{\sqrt 3 }}{4} \times 6 \times 6 \times \frac{1}{9}} \right) \cr
& \Rightarrow y = \sqrt 3 \cr} $$
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