A well has to be dug out that is to be 22.5 m deep and of diameter 7 m. Find the cost of plastering the inner curved surface at Rs. 3 per sq.meter :
A. Rs. 1465
B. Rs. 1475
C. Rs. 1485
D. Rs. 1495
Answer: Option C
Solution(By Examveda Team)
Curved surface area :$$\eqalign{ & = 2\pi rh \cr & = \left( {2 \times \frac{{22}}{7} \times \frac{7}{2} \times 22.5} \right){{\text{m}}^2} \cr & = 495{\text{ }}{{\text{m}}^2} \cr} $$
∴ Cost of plastering :
= Rs. (495 × 3)
= Rs. 1485
Related Questions on Volume and Surface Area
A. 12$$\pi$$ cm3
B. 15$$\pi$$ cm3
C. 16$$\pi$$ cm3
D. 20$$\pi$$ cm3
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A. 75 cu. m
B. 750 cu. m
C. 7500 cu. m
D. 75000 cu. m
A. 84 meters
B. 90 meters
C. 168 meters
D. 336 meters
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