According to Chilton-Colburn analogy for mass transfer, $${{\text{N}}_{{\text{St}}}}.{{\text{N}}_{{\text{Sc}}}}^{\frac{2}{3}}$$ is equal to
A. f
B. $$\frac{{\text{f}}}{2}$$
C. 2f
D. $$\frac{1}{{\text{f}}}$$
Answer: Option B
This Question Belongs to Chemical Engineering >> Mass Transfer
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