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Login𝑎
a, in m²/m³) for a gas-liquid dispersion, we use the formula:
𝑎
=
6
⋅
𝜀
𝑔
𝑑
𝑏
a=
d
b
6⋅ε
g
Where:
𝜀
𝑔
ε
g
= gas holdup (fractional)
𝑑
𝑏
d
b
= bubble diameter (in meters)
Given:
𝜀
𝑔
=
0.1
ε
g
=0.1
𝑑
𝑏
=
0.5
mm
=
0.0005
m
d
b
=0.5mm=0.0005m
Substituting into the formula:
𝑎
=
6
×
0.1
0.0005
=
0.6
0.0005
=
1200
m
2
/
m
3
a=
0.0005
6×0.1
=
0.0005
0.6
=1200m
2
/m
3
✅ Correct answer:
B. 1200
a = 6 × ε / d
where:
ε = fractional hold-up of gas = 0.1
d = gas bubble diameter = 0.5 mm = 0.0005 m
Substituting the values:
a = 6 × 0.1 / 0.0005
= 6 × 200
= 1200 m²/m³
So, the interfacial area per unit volume of dispersion is 1200 m²/m³.
a = 1200
Option B is Right