The interfacial area per unit volume of dispersion, in a gas-liquid contactor, for fractional hold up of gas = 0.1 and gas bubble diameter = 0.5 mm is given by (in m2/m3)
A. 500
B. 1200
C. 900
D. 800
Answer: Option A
A. 500
B. 1200
C. 900
D. 800
Answer: Option A
A. Chemical properties
B. Physical properties
C. Degree of turbulence
D. Interfacial area
A. No change in theoretical
B. Marginal decrease in the number of
C. Major decrease in the number of
D. None of these
To calculate the interfacial area per unit volume (denoted as
𝑎
a, in m²/m³) for a gas-liquid dispersion, we use the formula:
𝑎
=
6
⋅
𝜀
𝑔
𝑑
𝑏
a=
d
b
6⋅ε
g
Where:
𝜀
𝑔
ε
g
= gas holdup (fractional)
𝑑
𝑏
d
b
= bubble diameter (in meters)
Given:
𝜀
𝑔
=
0.1
ε
g
=0.1
𝑑
𝑏
=
0.5
mm
=
0.0005
m
d
b
=0.5mm=0.0005m
Substituting into the formula:
𝑎
=
6
×
0.1
0.0005
=
0.6
0.0005
=
1200
m
2
/
m
3
a=
0.0005
6×0.1
=
0.0005
0.6
=1200m
2
/m
3
✅ Correct answer:
B. 1200
The interfacial area per unit volume of dispersion (a) can be calculated using the following formula:
a = 6 × ε / d
where:
ε = fractional hold-up of gas = 0.1
d = gas bubble diameter = 0.5 mm = 0.0005 m
Substituting the values:
a = 6 × 0.1 / 0.0005
= 6 × 200
= 1200 m²/m³
So, the interfacial area per unit volume of dispersion is 1200 m²/m³.
Formula for interfacial Area per unit volume = 6 (1-e)/Dp
a = 1200
Option B is Right
Answer is B.