An object having 10 kg mass weighs 9.81kg on a spring balance. The value of ‘g’ at this place is
A. 10 m/sec2
B. 9.81 m/sec2
C. 10.2 m/sec2
D. 9.75 m/sec2
Answer: Option A
This Question Belongs to Civil Engineering >> Hydraulics And Fluid Mechanics
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A. 22.5 m/sec.
B. 33 m/sec.
C. 40 m/sec.
D. 90 m/sec.
A. the weight of the body
B. more than the weight of the body
C. less than the weight of the body
D. weight of the fluid displaced by the body
The difference of pressure between the inside and outside of a liquid drop is
A. $${\text{p}} = {\text{T}} \times {\text{r}}$$
B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$
C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$
D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$
A. cannot be subjected to shear forces
B. always expands until it fills any container
C. has the same shear stress.at a point regardless of its motion
D. cannot remain at rest under action of any shear force
Wrong question .. how can mass be variable(both in kg)
Question is WRONG
We know mass is universal for an object it is the weight that vary.
In question it says mass (since both in kilogram not newton) at one place and another place its different due to different value of g and we have find that different value of g.
This contradict laws of Physics
Although if we consider mass as variable than g comes to be 10 m/sec
By, say 10kg x 9.81m/sec²= 981 N
While measuring in spring balance 9.81 kg(which is not possible)x g m/sec ² = 9.8 g
comparing both we get value of g as 10m/se
For eg : If we measure 10kg rice at earth and 10 kg at moon in both case value of weight is different.
IF OBJECT WEIGHS LESS THEN THERE SHOULD BE LESS g AT THAT PLACES.ANSWER OF ABOVE QUESTION SHOULD BE 9.62 M/S2,SO NOT A SINGLE OPTION IS TRUE.
Mass-10kg
i.e-m×g=10×9.81=98.1
=(98.1)÷(9.81)=10m/sec square