An observer 2 m tall is $$10\sqrt 3 $$ m away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The height of the tower is:
A. 14 m
B. 12 m
C. 10 m
D. None of these
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & SR = PQ = 2\,m \cr & PS = QR = 10\sqrt 3 \,m \cr & \tan {30^ \circ } = \frac{{TS}}{{PS}} \cr & \frac{1}{{\sqrt 3 }} = \frac{{TS}}{{10\sqrt 3 }} \cr & TS = \frac{{10\sqrt 3 }}{{\sqrt 3 }} = 10\,m \cr & TR = TS + SR = 10 + 2 = 12\,m \cr} $$
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