An OR gate has 6 inputs. The number of input words in its truth table are
A. 6
B. 32
C. 64
D. 128
Answer: Option C
Solution (By Examveda Team)
A truth table shows all possible combinations of inputs and the corresponding output of a logic gate.For a gate with 'n' inputs, the number of possible input combinations (or input words) is calculated as 2 raised to the power of n (2n).
In this case, the OR gate has 6 inputs.
So, the number of input words in its truth table is 26 = 2 * 2 * 2 * 2 * 2 * 2 = 64.
This Question Belongs to Electronics And Communications Engineering >> Digital Electronics
For an n-input gate, truth table has 2^𝑛 input combinations. Here
2^6=64
OR gate has only two input 0 and 1.....2^n
so.. the ques gives 6 input
therefore 2^6=64
2 power 6
2*2*2*2*2*2=64
2 power 6=64
2^6=64
Plz explain,why it's answer will be 64?