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An OR gate has 6 inputs. The number of input words in its truth table are
Answer & Solution
Correct Answer:
Option
C
A truth table shows all possible combinations of inputs and the corresponding output of a logic gate.
For a gate with 'n' inputs, the number of possible input combinations (or input words) is calculated as 2 raised to the power of n (2n).
In this case, the OR gate has 6 inputs.
So, the number of input words in its truth table is 26 = 2 * 2 * 2 * 2 * 2 * 2 = 64.
For a gate with 'n' inputs, the number of possible input combinations (or input words) is calculated as 2 raised to the power of n (2n).
In this case, the OR gate has 6 inputs.
So, the number of input words in its truth table is 26 = 2 * 2 * 2 * 2 * 2 * 2 = 64.
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Login2^6=64
so.. the ques gives 6 input
therefore 2^6=64
2*2*2*2*2*2=64