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Pipes And Cistern - Aptitude MCQ Questions and Solutions with Explanations

Pipes And Cistern MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Pipes And Cistern with easy and logical explanations. Pipes And Cistern MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-6 section-1

51
A pump can fill a tank will water in 1 hour. Because of a leak, it took $$1\frac{1}{3}$$ hours to fill the tank. In how many hours can the leak alone drain all the water of the tank when it is full?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let A and B are pipe and leakage
Pipes and Cistern mcq question image
B = 1 efficiently
B = $$\frac{4}{1}$$ = 4 hrs
52
Pipes A, B and C can fill a tank in 20, 30 and 60 hours, respectively. Pipes A, B and C are opened at 7 a.m., 8 a.m. and 9 a.m., respectively, on the same day. When will the tank be full?
Discuss
Answer & Solution
Answer: Option D
Solution:
Pipes and Cistern mcq question image
Pipe A till 9 O'clock = 3 × 2 = 6
Pipe B till 9 O'clock = 2 × 1 = 2
Remaining work = 60 - 6 - 2 = 52
Time = $$\frac{{52}}{6}$$
= $$8\frac{4}{6}$$
= 8 hrs 40 min
= 9:00 + 8 hrs 40 min
= 05:40 pm
53
Pipes A and B are filling pipes while pipe C is an emptying pipe. A and B can fill a tank in 72 and 90 minutes respectively. When all the three pipes are opened together, the tank gets filled in 2 hours. A and B are opened together for 12 minutes, then closed and C is opened. The tank will be empty after:
Discuss
Answer & Solution
Answer: Option C
Solution:
Pipes and Cistern mcq question image
A + B - C = 3
5 + 4 - C = 3
C = 6
In 12 min, (A + B) can fill = (5 + 4) × 12 = 9 × 12
The time was taken to empty (9 × 12) by 'C'
Time $$ = \frac{{9 \times 12}}{6} = 18\min $$
54
Two pipes A and B can fill cistern in $$12\frac{1}{2}$$ hours and 25 hours, respectively. The pipes were opened simultaneously, and it was found that, due to leakage in the bottom, it took one hour 40 minutes more to fill the cistern. It the cistern is full, in how much time (in hours) will the leak alone empty 70% of the cistern?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & A = 12\frac{1}{2} = \frac{{25}}{2} \cr & B = 25 \cr} $$
Pipes and Cistern mcq question image
$$\eqalign{ & A + B = \frac{{25}}{{2 + 1}} = \frac{{25}}{3} \cr & = 8\,{\text{hr }}20\,\min \cr & A + B - C \cr & = 8\,{\text{hr }}20\,\min + 1\,{\text{hr 4}}0\,\min \cr & = 10{\text{ hr}} \cr} $$
Pipes and Cistern mcq question image
C = 8 + 4 - 10 = 2
70% of tank capacity $$ = 100 \times \frac{{70}}{{100}} = 70$$
Time taken in leakage $$ = \frac{{70}}{2} = 35\,{\text{hrs}}$$
55
When operated separately pipe A takes 5 hours less than pipe B to fill a cistern, and when operated together, the cistern gets filled in 6 hours. In how much time (in hours) will pipe A fill the cistern, if operated separately?
Discuss
Answer & Solution
Answer: Option A
Solution:
\[\begin{array}{*{20}{c}} {\text{B}}&{}&{\text{A}} \\ {x + 5}&:&x \end{array}\]
Now go through option,
Let A = 10 hours
B = 15 hours
Pipes and Cistern mcq question image
A + B = $$\frac{{30}}{5}$$ = 6 hours
56
The volume of a tank is 72 cubic metres. Water is poured into it at the rate of 60 litres per minute. How much time will it take to fill the tank?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & t = \frac{{7200}}{{60}}\min \cr & = 1200\min \cr & = \frac{{1200}}{{60}}{\text{ hours}} \cr & = 20{\text{ hours}} \cr} $$
57
6 pipes, working 10 hours a day, can empty a cistern in 3 days. How many hours a day must 9 pipes work to empty the cistern in one day?
Discuss
Answer & Solution
Answer: Option A
Solution:
6 × 10 × 3 = 9 × x × 1
x = 20 Answer
58
Tap A can fill a tank in 6 hours, tap B can fill the same tank in 8 hours and tap C can empty the same tank in 4 hours. If all three taps A, B and C are opened together, then how much time (in hours) will be taken to fill the tank?
Discuss
Answer & Solution
Answer: Option A
Solution:
Pipes and Cistern mcq question image
Total work in a hours by (A + B + C) = 4 + 3 - 6 = 1
A + B + C = $$\frac{{24}}{1}$$ = 24 hours
59
Two pipes A and B can fill an empty tank in 10 hours and 15 hours respectively. Pipe C alone can empty the completely filled tank in 12 hours. First both pipes A and B are opened and after 5 hours pipe C is also opened. What is the total time (in hours) in which then tank will be filled?
Discuss
Answer & Solution
Answer: Option A
Solution:
Pipes and Cistern mcq question image
According to question,
Efficiency of (A + B) = 18 + 12 = 30 litre/hr
In 5 hrs, filled capacity by (A + B) = 30 × 5 = 150 litres
∴ Remaining capacity = 180 - 150 = 30 litres
Total efficiency of (A + B + C) = 18 + 12 - 15 = 15 litre/hr
∴ Time taken by (A + B + C) to fill the remaining capacity
$$ \Rightarrow \frac{{30}}{{15}} = 2\,{\text{hrs}}$$
∴ Required time, to fill the complete tank = 5 hrs + 2 hrs = 7 hrs
60
Pipes A, B and C can fill a tank is 15, 30 and 40 hours, respectively. Pipes A, B and C are opened at 6 a.m., 8 a.m. and 10 a.m., respectively, on the same day. When will the tank be full?
Discuss
Answer & Solution
Answer: Option A
Solution:
Pipes and Cistern mcq question image
A → 6 am → 10 am = 4 × 8 = 32
B → 8 am → 10 am = 2 × 4 = 8
120 - 40 = 80
A + B + C = $$\frac{{80}}{{15}}$$ = 5 hr 20 min
10 am + 5 hr 20 min
3 : 20 pm