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When operated separately pipe A takes 5 hours less than pipe B to fill a cistern, and when operated together, the cistern gets filled in 6 hours. In how much time (in hours) will pipe A fill the cistern, if operated separately?
Answer & Solution
Correct Answer:
Option
A
\[\begin{array}{*{20}{c}}
{\text{B}}&{}&{\text{A}} \\
{x + 5}&:&x
\end{array}\]
Now go through option,
Let A = 10 hours
B = 15 hours
A + B = $$\frac{{30}}{5}$$ = 6 hours
Now go through option,
Let A = 10 hours
B = 15 hours
A + B = $$\frac{{30}}{5}$$ = 6 hours
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