Ashok left from place A for place B at 8 am and Rahul left place B for place A at 10.00 am the distance between place A and B is 637 km. If Ashok and Rahul are travelling at a uniform speed of 39 kmph and 47 kmph respectively, at what time will they meet ?
A. 5.30 pm
B. 4.30 pm
C. 5 pm
D. 4 pm
Answer: Option B
Solution(By Examveda Team)
Speed of Ashok = 39 km/phSpeed of Rahul = 47 km/ph
Distance between place A and place B = 637 km
Distance covered by Ashok (from 8 am to 10 am) in 2 hours = 2 × 39 = 78 km
∴ Remaining distance = 637 - 78 = 559
Relative speed = 39 + 47 = 86 km/ph
∴ Time taken to travel 559 km = $$\frac{559}{86}$$ = 6.5 hours
So, they meet at = (10 am + 6.5 hrs) = 4.30 pm
This Question Belongs to Arithmetic Ability >> Speed Time And Distance
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D. 62 min.
E. 66 min.
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