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Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes ?
Answer & Solution
Correct Answer:
Option
C
Let the speed of the man be x km/hr
Then, Distance covered by the bus in 2 minutes = Distance covered by the man in 8 min
$$\eqalign{ & \Rightarrow 20 \times \frac{2}{{60}} = x \times \frac{8}{{60}} \cr & \Rightarrow x = \left( {\frac{2}{3} \times \frac{{60}}{8}} \right) \cr & \Rightarrow x = 5{\text{ km/hr}} \cr} $$
Then, Distance covered by the bus in 2 minutes = Distance covered by the man in 8 min
$$\eqalign{ & \Rightarrow 20 \times \frac{2}{{60}} = x \times \frac{8}{{60}} \cr & \Rightarrow x = \left( {\frac{2}{3} \times \frac{{60}}{8}} \right) \cr & \Rightarrow x = 5{\text{ km/hr}} \cr} $$
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