Solution:
In this C program, the expression
i++ || j++ || k++ involves the logical OR (
||) operator. Here's how it works:
- It evaluates from left to right.
- It stops evaluating as soon as it finds a true condition because in a logical OR operation, if one operand is true, the result is true.
Let's break it down step by step:
-
i is initially 0.
i++ returns 0 (post-increment), but it increments
i to 1.
-
j is initially 1.
j++ returns 1 (post-increment), and it increments
j to 2.
-
k is initially 2.
k++ returns 2 (post-increment), and it increments
k to 3.
Now, the expression is evaluated:
-
0 || 1 is true because one of the operands is true.
- Since the result is true, the evaluation stops.
After the evaluation:
-
m is assigned the value 1 because the result is true.
-
i is 1 because
i was incremented during the evaluation.
-
j is 2 because
j was incremented during the evaluation.
-
k is 2 because
k was not incremented further.
Therefore, the output of the
printf statement is
1 1 2 2, which corresponds to Option B.