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41
In case of vapour compression refrigeration system, elevating the evaporator temperature (keeping the condenser temperature constant) results in
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Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
42
Melting of ice is an example of an __________ process.
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Answer & Solution
Answer: Option B
Solution:
Since during the phase changes normally the temperature and pressure remains constant we call melting of ice an isothermal process.
43
Claude's liquefaction process employs the cooling of gases by
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Answer & Solution
Answer: Option A
Solution:
Claude’s liquefaction process employs cooling of gas by expansion in engine.
44
A domestic refrigerator has a/an __________ cooled condenser.
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Answer & Solution
Answer: Option B
Solution:
A domestic refrigerator contains air as an cooled condenser.
45
Pressure-enthalpy chart is useful in refrigeration. The change in internal energy of an ideal fluid used in ideal refrigeration cycle is
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Answer & Solution
Answer: Option C
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46
At normal boiling point, molar entropy of vaporisation is __________ Joule/K°.mole.
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Answer & Solution
Answer: Option B
Solution:
Here the substance should be mentioned for which vaporization is taking place.
47
PVy = constant, holds good for an isentropic process, which is
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Answer & Solution
Answer: Option C
Solution:
We know from second law of thermodynamics for an reversible process $$Tds = \delta Q$$
So, $$dS =0$$
When the process is adiabatic.
Hence for a reversible adiabatic process the entropy is constant.
48
The internal energy of an ideal gas is a function of its __________ only.
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Answer & Solution
Answer: Option D
Solution:
The internal energy of an substance is given by
$$\eqalign{ & dU = CvdT - \left[ {P + T\left( {\frac{{\left( {\frac{{\partial V}}{{\partial T}}} \right)p}}{{\left( {\frac{{\partial V}}{{\partial P}}} \right)T}}} \right)dV} \right] \cr & {\text{For an ideal gas, }}PV = RT \cr & {\text{So, }}\left( {\frac{{\partial V}}{{\partial T}}} \right)p = \frac{R}{P}\,\,{\text{and }}\left( {\frac{{\partial V}}{{\partial P}}} \right)T = - \frac{{RT}}{{{P^2}}} \cr & {\text{Hence, }}dU = CvdT \cr} $$
So internal energy is only an function of temperature.
49
Gibbs free energy at constant pressure and temperature under equilibrium conditions is
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Answer & Solution
Answer: Option D
Solution:
The gibbs free energy change as given by second law of thermodynamics goes on decreasing for an spontaneous irreversible process of constant temperature and pressure and finally when it is reached equilibrium the change is zero. Hence we can say a minimum exists for gibbs free energy.
50
Free energy change at equilibrium is
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Answer & Solution
Answer: Option A
Solution:
The gibbs free energy change as given by second law of thermodynamics goes on decreasing for an spontaneous irreversible process of constant temperature and pressure and finally when it is reached equilibrium the change is zero. Hence we can say a minimum exists for gibbs free energy.