Deuteron in its ground state has a total angular momentum J = 1 and a positive parity. The corresponding orbital angular momentum L and spin angular momentum S combinations are
A. L = 0, S = 1 and L = 2, S = 0
B. L = 0, S = 1 and L = 1, S = 1
C. L = 0, S = 1 and L = 2, S = 1
D. L = 1, S = 1 and L = 2, S = 1
Answer: Option C
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