Dimensions of surface tension are
A. ML0T2
B. ML0T-2
C. ML1T-2
D. ML-1T-2
Answer: Option B
Solution (By Examveda Team)
We know that Surface Tension (σ) = Force / LengthStep-by-Step Dimensional Analysis:
1. Dimensional Formula of Force (F):
- Force = Mass × Acceleration
- Acceleration = Length / Time² = LT-2
- So, Force = M × LT-2 = MLT-2
2. Dimensional Formula of Length (L):
- L = L1
3. Dividing Force by Length:
- σ = (MLT-2) / L
- σ = ML(1-1)T-2 = ML0T-2
Thus, the correct dimensional formula for surface tension is ML0T-2, making Option B the correct choice.
This Question Belongs to Civil Engineering >> Hydraulics And Fluid Mechanics
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Comments (5)
A. 22.5 m/sec.
B. 33 m/sec.
C. 40 m/sec.
D. 90 m/sec.
A. the weight of the body
B. more than the weight of the body
C. less than the weight of the body
D. weight of the fluid displaced by the body
The difference of pressure between the inside and outside of a liquid drop is
A. $${\text{p}} = {\text{T}} \times {\text{r}}$$
B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$
C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$
D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$
A. cannot be subjected to shear forces
B. always expands until it fills any container
C. has the same shear stress.at a point regardless of its motion
D. cannot remain at rest under action of any shear force
Answer will be "B"
MT−2
Answer B
Surface tention = N/m
N= Newton
M= meter
N= kg.m/sec^2=M^1 L^1 T^-2] /M=[L^-1] Therefore, surface tension is dimensionally represented as M^1L^° T^-2.
Wrong