Due to inclement weather, an Aeroplane reduce its speed by 300 km/hr and reached the destination of 1200 km late by 2 hours. Then the schedule duration of the flight was :

Solution (By Examveda Team)

Let the original speed of Aeroplane be x km/hr
$$\eqalign{ & \frac{{1200}}{{\left( {x - 300} \right)}} - \frac{{1200}}{x} = 2 \cr & \frac{{x - x + 300}}{{\left( {x - 300} \right)x}} = \frac{2}{{1200}} \cr} $$

Original time :
$$\eqalign{ & t = \frac{{1200}}{{600}} \cr & t = 2{\text{ hours}} \cr} $$