11. The impulse response of a linear time invariant system is h(n) = {1, \[\underline 2 \], 1, -1}. The response for the input signal x(n) = {\[\underline 1 \], 2, 3, 1} is
12. With the following equations, the time invariant systems are
$$\eqalign{
& 1.\,\frac{{{d^2}y\left( t \right)}}{{d{t^2}}} + 2t\frac{d}{{dt}}y\left( t \right) + 5y\left( t \right) = x\left( t \right) \cr
& 2.\,y\left( t \right) = {e^{ - 2x\left( t \right)}} \cr
& 3.\,y\left( t \right) = \left[ {\frac{d}{{dt}}x\left( t \right)} \right] \cr
& 4.\,y\left( t \right) = \frac{d}{{dt}}\left[ {{e^{ - 2t}}x\left( t \right)} \right] \cr} $$
$$\eqalign{ & 1.\,\frac{{{d^2}y\left( t \right)}}{{d{t^2}}} + 2t\frac{d}{{dt}}y\left( t \right) + 5y\left( t \right) = x\left( t \right) \cr & 2.\,y\left( t \right) = {e^{ - 2x\left( t \right)}} \cr & 3.\,y\left( t \right) = \left[ {\frac{d}{{dt}}x\left( t \right)} \right] \cr & 4.\,y\left( t \right) = \frac{d}{{dt}}\left[ {{e^{ - 2t}}x\left( t \right)} \right] \cr} $$
13. Two ideal quantizers A and B have following specifications:
A: 5 bit Quantizer with input dynamic range of -1V to +1V with Q1 as quantization noise power
B: 8 bit Quantizer with input dynamic range of -0.5V to +0.5V with Q2 as quantization noise power.
Then $$\frac{{{{\text{Q}}_1}}}{{{{\text{Q}}_2}}}$$ will be
A: 5 bit Quantizer with input dynamic range of -1V to +1V with Q1 as quantization noise power
B: 8 bit Quantizer with input dynamic range of -0.5V to +0.5V with Q2 as quantization noise power.
Then $$\frac{{{{\text{Q}}_1}}}{{{{\text{Q}}_2}}}$$ will be
14. The trigonometric Fourier series of an even function of time does not have
15. Laplace transform of 1 - e-at is given by
16. The dead band range of a first order IIR filter given by y(n) = 0.5y (n - 1) + x(n) on quantization operation due to rounding with a step size of is:
17. The filter used for pulse shaping is
18. For a function g(t), it is given that $$\int\limits_{ - \infty }^{ + \infty } {g\left( t \right){e^{ - j\omega t}}dt = \omega {e^{ - 2{\omega ^2}}}} $$ for any real value $$\omega .$$ If $$y\left( t \right) = \int\limits_{ - \infty }^t {g\left( \tau \right)d\tau ,} $$ then $$\int\limits_{ - \infty }^{ + \infty } {y\left( t \right)dt} $$ is . . . . . . . .
19. An LTI system has a wide-sense stationary (WSS) input signal with zero mean, Its output is
20. The Dirac delta function δ(t) is defined as
Read More Section(Signal Processing)
Each Section contains maximum 100 MCQs question on Signal Processing. To get more questions visit other sections.