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Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{Let}}\,{\text{the}}\,{\text{number}}\,{\text{be}}\,x \cr
& {\text{Then}},\,x + 17 = \frac{{60}}{x} \cr
& \Rightarrow {x^2} + 17x - 60 = 0 \cr
& \Rightarrow (x + 20)(x - 3) = 0 \cr
& \Rightarrow x = 3 \cr} $$
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