Find branch current IR2.

A. 5.4 mA
B. -5.4 mA
C. 113.0 mA
D. 119.6 mA
Answer: Option C
A. 5.4 mA
B. -5.4 mA
C. 113.0 mA
D. 119.6 mA
Answer: Option C
The branch current method uses.
A. Kirchhoff's voltage and current laws
B. Thevenin's theorem and Ohm's law
C. Kirchhoff's current law and Ohm's law
D. The superposition theorem and Thevenin's theorem
In assigning the direction of branch currents.
A. The directions are critical
B. The directions are not critical
C. They must point into a node
D. They must point out of a node
Pls solve this problem
assume voltage at node is Va, applying nodal analysis results in:
((Va-12)/68) + (Va/37) + ((Va-4)/90) = 0
solving the above equation results us Va = 4.181 V
therefore, IR2 = Va/R2 = 4.181/37 = 113 mA
)A silicon sample is uniformly doped with 10^16 phosphorus atoms/cm^3 and 2×10^16 boron atoms/cm^3. If all the dopants are fully ionized, the material is _______
p-type with carrier concentration of 10^16 /cm^3.
p-type with carrier concentration of 4×10^16 /cm^3.
n-type with carrier concentration of 3×10^16 /cm^3.
Intrinsic
How to solve
How to solve this question
How?