Find the equation of a circle whose diameter has end points (4, 3) and (-2, 1).
A. x2 + y2 - 2x - 4y = 3
B. x2 + y2 - 2x - 4y = 5
C. x2 + y2 - 6x + 2y = 3
D. x2 + y2 - 2x + 4y = 5
Answer: Option B
Solution (By Examveda Team)
Go through option,Points (4, 3) and (-2, 1) will satisfy the equation from option B, x2 + y2 - 2x - 4y = 5
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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