Find the whole number which when increased by 20 is equal to 69 times the reciprocal of the number.
A. 2.5
B. 3
C. 5
D. 7
Answer: Option B
Solution(By Examveda Team)
Let the required number be xThen,
$$\eqalign{ & \Leftrightarrow x + 20 = \frac{{69}}{x} \cr & \Leftrightarrow {x^2} + 20x - 69 = 0 \cr & \Leftrightarrow {x^2} + 23x - 3x - 69 = 0 \cr & \Leftrightarrow x\left( {x + 23} \right) - 3\left( {x + 23} \right) = 0 \cr & \Leftrightarrow \left( {x + 23} \right)\left( {x - 3} \right) = 0 \cr & \Leftrightarrow x = 3\,\,\,\,\,\,\,\,\,\left[ {\because x \ne - 23} \right] \cr} $$
Related Questions on Problems on Numbers
If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A. 35
B. 36
C. 45
D. 54
E. None of these
A. 9
B. 11
C. 13
D. 15
E. None of these
A. 3
B. 4
C. 9
D. Cannot be determined
E. None of these
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